34x^2-23x=0

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Solution for 34x^2-23x=0 equation: 



34x^2-23x=0

a = 34; b = -23; c = 0;
Δ = b2-4ac
Δ = -232-4·34·0
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-23}{2*34}=\frac{0}{68}
=0
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+23}{2*34}=\frac{46}{68}
=23/34
$

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